3D shapes and volumes
Geometry and measures
- Crossover
- Non-calculator
- 8 questions
- 29 marks
Questions marked Higher are aimed at the Higher tier.
These are original practice questions, not a past paper. This site is independent and not affiliated with AQA or Pearson.
-
A cuboid measures $3$ cm by $4$ cm by $5$ cm. Find its volume.
2 marks
-
A cube has side $4$ cm. Find its surface area.
2 marks
-
A cylinder has radius $3$ cm and height $10$ cm. Find its volume in terms of $\pi$.
3 marks
-
A prism has a triangular cross-section of area $12$ cm$^{2}$ and length $8$ cm. Find its volume.
3 marks
-
A cuboid measures $2$ cm by $3$ cm by $6$ cm. Find the length of a space diagonal.
Cuboid 6 cm by 3 cm by 2 cm 4 marks
-
A cone has radius $3$ cm and perpendicular height $4$ cm. Find its volume and its total surface area, including the base, in terms of $\pi$.
4 marks
-
A cuboid measures $8$ cm by $5$ cm by $3$ cm. Find the volume, the surface area and the space diagonal. Higher
5 marks
-
A cylinder has radius $5$ cm and height $12$ cm. A sphere has radius $5$ cm. Find both volumes in terms of $\pi$, and the extra volume of the cylinder. Higher
6 marks
Mark scheme
-
Answer. $60$ cm$^{3}$
- $3 \times 4 \times 5$
- $60$ cm$^{3}$
-
Answer. $96$ cm$^{2}$
- One face has area $16$.
- $6 \times 16 = 96$ cm$^{2}$
-
Answer. $90\pi$ cm$^{3}$
- $V = \pi r^{2} h$
- $\pi \times 9 \times 10 = 90\pi$ cm$^{3}$
-
Answer. $96$ cm$^{3}$
- Volume $= \text{area of cross-section} \times \text{length}$
- $96$ cm$^{3}$
-
Answer. $7$ cm
- $\sqrt{2^{2} + 3^{2} + 6^{2}} = \sqrt{49}$
- $7$ cm
-
Answer. Volume $12\pi$ cm$^{3}$, surface area $24\pi$ cm$^{2}$
- Volume $= \dfrac{1}{3}\pi r^{2} h = 12\pi$ cm$^{3}$.
- Slant height $= \sqrt{3^{2} + 4^{2}} = 5$ cm.
- Curved area $= \pi \times 3 \times 5 = 15\pi$, plus base $9\pi$, gives $24\pi$ cm$^{2}$.
-
Answer. Volume $120$ cm$^{3}$, surface area $158$ cm$^{2}$, diagonal $7\sqrt{2}$ cm
- Volume $= 8 \times 5 \times 3 = 120$ cm$^{3}$.
- Surface area $= 2(40 + 24 + 15) = 158$ cm$^{2}$.
- Diagonal $= \sqrt{64 + 25 + 9} = \sqrt{98} = 7\sqrt{2}$ cm.
-
Answer. Cylinder $300\pi$ cm$^{3}$, sphere $\dfrac{500\pi}{3}$ cm$^{3}$, difference $\dfrac{400\pi}{3}$ cm$^{3}$
- Cylinder $= \pi \times 25 \times 12 = 300\pi$ cm$^{3}$.
- Sphere $= \dfrac{4}{3}\pi \times 125 = \dfrac{500\pi}{3}$ cm$^{3}$.
- Difference $= 300\pi - \dfrac{500\pi}{3} = \dfrac{400\pi}{3}$ cm$^{3}$.